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X(3X+48)=180
We move all terms to the left:
X(3X+48)-(180)=0
We multiply parentheses
3X^2+48X-180=0
a = 3; b = 48; c = -180;
Δ = b2-4ac
Δ = 482-4·3·(-180)
Δ = 4464
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{4464}=\sqrt{144*31}=\sqrt{144}*\sqrt{31}=12\sqrt{31}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(48)-12\sqrt{31}}{2*3}=\frac{-48-12\sqrt{31}}{6} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(48)+12\sqrt{31}}{2*3}=\frac{-48+12\sqrt{31}}{6} $
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