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X(3X-3)=(3X+4)(X-1)
We move all terms to the left:
X(3X-3)-((3X+4)(X-1))=0
We multiply parentheses
3X^2-3X-((3X+4)(X-1))=0
We multiply parentheses ..
3X^2-((+3X^2-3X+4X-4))-3X=0
We calculate terms in parentheses: -((+3X^2-3X+4X-4)), so:We add all the numbers together, and all the variables
(+3X^2-3X+4X-4)
We get rid of parentheses
3X^2-3X+4X-4
We add all the numbers together, and all the variables
3X^2+X-4
Back to the equation:
-(3X^2+X-4)
3X^2-3X-(3X^2+X-4)=0
We get rid of parentheses
3X^2-3X^2-3X-X+4=0
We add all the numbers together, and all the variables
-4X+4=0
We move all terms containing X to the left, all other terms to the right
-4X=-4
X=-4/-4
X=1
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