X(3x-3)=(3x+4)(x-1)

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Solution for X(3x-3)=(3x+4)(x-1) equation: 



X(3X-3)=(3X+4)(X-1)

We move all terms to the left:

X(3X-3)-((3X+4)(X-1))=0

We multiply parentheses

3X^2-3X-((3X+4)(X-1))=0

We multiply parentheses ..

3X^2-((+3X^2-3X+4X-4))-3X=0



We calculate terms in parentheses: -((+3X^2-3X+4X-4)), so:

(+3X^2-3X+4X-4)

We get rid of parentheses

3X^2-3X+4X-4

We add all the numbers together, and all the variables

3X^2+X-4

Back to the equation:

-(3X^2+X-4)



We add all the numbers together, and all the variables

3X^2-3X-(3X^2+X-4)=0

We get rid of parentheses

3X^2-3X^2-3X-X+4=0

We add all the numbers together, and all the variables

-4X+4=0

We move all terms containing X to the left, all other terms to the right

-4X=-4

X=-4/-4

X=1

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