X(3x-4)-6(20x)=0

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Solution for X(3x-4)-6(20x)=0 equation:



X(3X-4)-6(20X)=0
We add all the numbers together, and all the variables
-620X+X(3X-4)=0
We multiply parentheses
3X^2-620X-4X=0
We add all the numbers together, and all the variables
3X^2-624X=0
a = 3; b = -624; c = 0;
Δ = b2-4ac
Δ = -6242-4·3·0
Δ = 389376
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{389376}=624$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-624)-624}{2*3}=\frac{0}{6} =0 $
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-624)+624}{2*3}=\frac{1248}{6} =208 $

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