X(3x-4)-6(20x)=0

Solution for X(3x-4)-6(20x)=0 equation:

X(3X-4)-6(20X)=0

We add all the numbers together, and all the variables

-620X+X(3X-4)=0

We multiply parentheses

3X^2-620X-4X=0

We add all the numbers together, and all the variables

3X^2-624X=0

a = 3; b = -624; c = 0;
Δ = b2-4ac
Δ = -6242-4·3·0
Δ = 389376
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{389376}=624$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-624)-624}{2*3}=\frac{0}{6}
=0
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-624)+624}{2*3}=\frac{1248}{6}
=208
$