X(3x-7)=(3x+3)(x-4)

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Solution for X(3x-7)=(3x+3)(x-4) equation: 



X(3X-7)=(3X+3)(X-4)

We move all terms to the left:

X(3X-7)-((3X+3)(X-4))=0

We multiply parentheses

3X^2-7X-((3X+3)(X-4))=0

We multiply parentheses ..

3X^2-((+3X^2-12X+3X-12))-7X=0



We calculate terms in parentheses: -((+3X^2-12X+3X-12)), so:

(+3X^2-12X+3X-12)

We get rid of parentheses

3X^2-12X+3X-12

We add all the numbers together, and all the variables

3X^2-9X-12

Back to the equation:

-(3X^2-9X-12)



We add all the numbers together, and all the variables

3X^2-7X-(3X^2-9X-12)=0

We get rid of parentheses

3X^2-3X^2-7X+9X+12=0

We add all the numbers together, and all the variables

2X+12=0

We move all terms containing X to the left, all other terms to the right

2X=-12

X=-12/2

X=-6

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