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X(4X+16)=28
We move all terms to the left:
X(4X+16)-(28)=0
We multiply parentheses
4X^2+16X-28=0
a = 4; b = 16; c = -28;
Δ = b2-4ac
Δ = 162-4·4·(-28)
Δ = 704
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{704}=\sqrt{64*11}=\sqrt{64}*\sqrt{11}=8\sqrt{11}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(16)-8\sqrt{11}}{2*4}=\frac{-16-8\sqrt{11}}{8} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(16)+8\sqrt{11}}{2*4}=\frac{-16+8\sqrt{11}}{8} $
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