X(4x+20)=68

Solution for X(4x+20)=68 equation:

X(4X+20)=68

We move all terms to the left:

X(4X+20)-(68)=0

We multiply parentheses

4X^2+20X-68=0

a = 4; b = 20; c = -68;
Δ = b2-4ac
Δ = 202-4·4·(-68)
Δ = 1488
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1488}=\sqrt{16*93}=\sqrt{16}*\sqrt{93}=4\sqrt{93}$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(20)-4\sqrt{93}}{2*4}=\frac{-20-4\sqrt{93}}{8}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(20)+4\sqrt{93}}{2*4}=\frac{-20+4\sqrt{93}}{8}
$