X(4x+33)=70

Solution for X(4x+33)=70 equation:

X(4X+33)=70

We move all terms to the left:

X(4X+33)-(70)=0

We multiply parentheses

4X^2+33X-70=0

a = 4; b = 33; c = -70;
Δ = b2-4ac
Δ = 332-4·4·(-70)
Δ = 2209
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2209}=47$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(33)-47}{2*4}=\frac{-80}{8}
=-10
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(33)+47}{2*4}=\frac{14}{8}
=1+3/4
$