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X(4X+5)=20X
We move all terms to the left:
X(4X+5)-(20X)=0
We add all the numbers together, and all the variables
-20X+X(4X+5)=0
We multiply parentheses
4X^2-20X+5X=0
We add all the numbers together, and all the variables
4X^2-15X=0
a = 4; b = -15; c = 0;
Δ = b2-4ac
Δ = -152-4·4·0
Δ = 225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{225}=15$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-15)-15}{2*4}=\frac{0}{8} =0 $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-15)+15}{2*4}=\frac{30}{8} =3+3/4 $
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