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X(4X+6)=35
We move all terms to the left:
X(4X+6)-(35)=0
We multiply parentheses
4X^2+6X-35=0
a = 4; b = 6; c = -35;
Δ = b2-4ac
Δ = 62-4·4·(-35)
Δ = 596
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{596}=\sqrt{4*149}=\sqrt{4}*\sqrt{149}=2\sqrt{149}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-2\sqrt{149}}{2*4}=\frac{-6-2\sqrt{149}}{8} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+2\sqrt{149}}{2*4}=\frac{-6+2\sqrt{149}}{8} $
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