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X(4X+7)=240
We move all terms to the left:
X(4X+7)-(240)=0
We multiply parentheses
4X^2+7X-240=0
a = 4; b = 7; c = -240;
Δ = b2-4ac
Δ = 72-4·4·(-240)
Δ = 3889
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-\sqrt{3889}}{2*4}=\frac{-7-\sqrt{3889}}{8} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+\sqrt{3889}}{2*4}=\frac{-7+\sqrt{3889}}{8} $
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