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X(4X+9)=180
We move all terms to the left:
X(4X+9)-(180)=0
We multiply parentheses
4X^2+9X-180=0
a = 4; b = 9; c = -180;
Δ = b2-4ac
Δ = 92-4·4·(-180)
Δ = 2961
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{2961}=\sqrt{9*329}=\sqrt{9}*\sqrt{329}=3\sqrt{329}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-3\sqrt{329}}{2*4}=\frac{-9-3\sqrt{329}}{8} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+3\sqrt{329}}{2*4}=\frac{-9+3\sqrt{329}}{8} $
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