X(4x-7)=(4x+2)(x-2)

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Solution for X(4x-7)=(4x+2)(x-2) equation: 



X(4X-7)=(4X+2)(X-2)

We move all terms to the left:

X(4X-7)-((4X+2)(X-2))=0

We multiply parentheses

4X^2-7X-((4X+2)(X-2))=0

We multiply parentheses ..

4X^2-((+4X^2-8X+2X-4))-7X=0



We calculate terms in parentheses: -((+4X^2-8X+2X-4)), so:

(+4X^2-8X+2X-4)

We get rid of parentheses

4X^2-8X+2X-4

We add all the numbers together, and all the variables

4X^2-6X-4

Back to the equation:

-(4X^2-6X-4)



We add all the numbers together, and all the variables

4X^2-7X-(4X^2-6X-4)=0

We get rid of parentheses

4X^2-4X^2-7X+6X+4=0

We add all the numbers together, and all the variables

-1X+4=0

We move all terms containing X to the left, all other terms to the right

-X=-4

X=-4/-1

X=+4

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