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X(5-2X)+15=0
We add all the numbers together, and all the variables
X(-2X+5)+15=0
We multiply parentheses
-2X^2+5X+15=0
a = -2; b = 5; c = +15;
Δ = b2-4ac
Δ = 52-4·(-2)·15
Δ = 145
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-\sqrt{145}}{2*-2}=\frac{-5-\sqrt{145}}{-4} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+\sqrt{145}}{2*-2}=\frac{-5+\sqrt{145}}{-4} $
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