X(5-3)=2(x+4)

Solution for X(5-3)=2(x+4) equation:

X(5-3)=2(X+4)

We move all terms to the left:

X(5-3)-(2(X+4))=0

We add all the numbers together, and all the variables

X2-(2(X+4))=0

We add all the numbers together, and all the variables

X^2-(2(X+4))=0


We calculate terms in parentheses: -(2(X+4)), so:

2(X+4)

We multiply parentheses

2X+8

Back to the equation:

-(2X+8)


We get rid of parentheses

X^2-2X-8=0

a = 1; b = -2; c = -8;
Δ = b2-4ac
Δ = -22-4·1·(-8)
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36}=6$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-6}{2*1}=\frac{-4}{2}
=-2
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+6}{2*1}=\frac{8}{2}
=4
$