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X(5X+10)=6
We move all terms to the left:
X(5X+10)-(6)=0
We multiply parentheses
5X^2+10X-6=0
a = 5; b = 10; c = -6;
Δ = b2-4ac
Δ = 102-4·5·(-6)
Δ = 220
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{220}=\sqrt{4*55}=\sqrt{4}*\sqrt{55}=2\sqrt{55}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-2\sqrt{55}}{2*5}=\frac{-10-2\sqrt{55}}{10} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+2\sqrt{55}}{2*5}=\frac{-10+2\sqrt{55}}{10} $
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