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X(5X-7)=36
We move all terms to the left:
X(5X-7)-(36)=0
We multiply parentheses
5X^2-7X-36=0
a = 5; b = -7; c = -36;
Δ = b2-4ac
Δ = -72-4·5·(-36)
Δ = 769
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-\sqrt{769}}{2*5}=\frac{7-\sqrt{769}}{10} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+\sqrt{769}}{2*5}=\frac{7+\sqrt{769}}{10} $
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