X(5y-7)=4(y-3)

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Solution for X(5y-7)=4(y-3) equation: 



X(5X-7)=4(X-3)

We move all terms to the left:

X(5X-7)-(4(X-3))=0

We multiply parentheses

5X^2-7X-(4(X-3))=0



We calculate terms in parentheses: -(4(X-3)), so:

4(X-3)

We multiply parentheses

4X-12

Back to the equation:

-(4X-12)



We get rid of parentheses

5X^2-7X-4X+12=0

We add all the numbers together, and all the variables

5X^2-11X+12=0

a = 5; b = -11; c = +12;
Δ = b2-4ac
Δ = -112-4·5·12
Δ = -119
Delta is less than zero, so there is no solution for the equation

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