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X(6X+3)=3
We move all terms to the left:
X(6X+3)-(3)=0
We multiply parentheses
6X^2+3X-3=0
a = 6; b = 3; c = -3;
Δ = b2-4ac
Δ = 32-4·6·(-3)
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{81}=9$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-9}{2*6}=\frac{-12}{12} =-1 $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+9}{2*6}=\frac{6}{12} =1/2 $
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