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X(6X+7)=26
We move all terms to the left:
X(6X+7)-(26)=0
We multiply parentheses
6X^2+7X-26=0
a = 6; b = 7; c = -26;
Δ = b2-4ac
Δ = 72-4·6·(-26)
Δ = 673
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-\sqrt{673}}{2*6}=\frac{-7-\sqrt{673}}{12} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+\sqrt{673}}{2*6}=\frac{-7+\sqrt{673}}{12} $
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