X(7-4y)=5y-1

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Solution for X(7-4y)=5y-1 equation:



X(7-4X)=5X-1
We move all terms to the left:
X(7-4X)-(5X-1)=0
We add all the numbers together, and all the variables
X(-4X+7)-(5X-1)=0
We multiply parentheses
-4X^2+7X-(5X-1)=0
We get rid of parentheses
-4X^2+7X-5X+1=0
We add all the numbers together, and all the variables
-4X^2+2X+1=0
a = -4; b = 2; c = +1;
Δ = b2-4ac
Δ = 22-4·(-4)·1
Δ = 20
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{20}=\sqrt{4*5}=\sqrt{4}*\sqrt{5}=2\sqrt{5}$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2\sqrt{5}}{2*-4}=\frac{-2-2\sqrt{5}}{-8} $
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2\sqrt{5}}{2*-4}=\frac{-2+2\sqrt{5}}{-8} $

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