X(X-1)=x(X+1)+2(X+4)

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Solution for X(X-1)=x(X+1)+2(X+4) equation:



X(X-1)=X(X+1)+2(X+4)
We move all terms to the left:
X(X-1)-(X(X+1)+2(X+4))=0
We multiply parentheses
X^2-1X-(X(X+1)+2(X+4))=0
We calculate terms in parentheses: -(X(X+1)+2(X+4)), so:
X(X+1)+2(X+4)
We multiply parentheses
X^2+X+2X+8
We add all the numbers together, and all the variables
X^2+3X+8
Back to the equation:
-(X^2+3X+8)
We get rid of parentheses
X^2-X^2-1X-3X-8=0
We add all the numbers together, and all the variables
-4X-8=0
We move all terms containing X to the left, all other terms to the right
-4X=8
X=8/-4
X=-2

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