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X(X+1)+7=5X+3
We move all terms to the left:
X(X+1)+7-(5X+3)=0
We multiply parentheses
X^2+X-(5X+3)+7=0
We get rid of parentheses
X^2+X-5X-3+7=0
We add all the numbers together, and all the variables
X^2-4X+4=0
a = 1; b = -4; c = +4;
Δ = b2-4ac
Δ = -42-4·1·4
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$X=\frac{-b}{2a}=\frac{4}{2}=2$
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