X(x+1)+8=(x+2)(x-2)

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Solution for X(x+1)+8=(x+2)(x-2) equation: 



X(X+1)+8=(X+2)(X-2)

We move all terms to the left:

X(X+1)+8-((X+2)(X-2))=0

We use the square of the difference formula

X^2+X(X+1)+4+8=0

We multiply parentheses

X^2+X^2+X+4+8=0

We add all the numbers together, and all the variables

2X^2+X+12=0

a = 2; b = 1; c = +12;
Δ = b2-4ac
Δ = 12-4·2·12
Δ = -95
Delta is less than zero, so there is no solution for the equation

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