X(x+1)-(x+2)(x-3)=7

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Solution for X(x+1)-(x+2)(x-3)=7 equation: 



X(X+1)-(X+2)(X-3)=7

We move all terms to the left:

X(X+1)-(X+2)(X-3)-(7)=0

We multiply parentheses

X^2+X-(X+2)(X-3)-7=0

We multiply parentheses ..

X^2-(+X^2-3X+2X-6)+X-7=0

We get rid of parentheses

X^2-X^2+3X-2X+X+6-7=0

We add all the numbers together, and all the variables

2X-1=0

We move all terms containing X to the left, all other terms to the right

2X=1

X=1/2

X=1/2

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