X(x+1)=(x-3)(x+7)

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Solution for X(x+1)=(x-3)(x+7) equation: 



X(X+1)=(X-3)(X+7)

We move all terms to the left:

X(X+1)-((X-3)(X+7))=0

We multiply parentheses

X^2+X-((X-3)(X+7))=0

We multiply parentheses ..

X^2-((+X^2+7X-3X-21))+X=0



We calculate terms in parentheses: -((+X^2+7X-3X-21)), so:

(+X^2+7X-3X-21)

We get rid of parentheses

X^2+7X-3X-21

We add all the numbers together, and all the variables

X^2+4X-21

Back to the equation:

-(X^2+4X-21)



We add all the numbers together, and all the variables

X^2+X-(X^2+4X-21)=0

We get rid of parentheses

X^2-X^2+X-4X+21=0

We add all the numbers together, and all the variables

-3X+21=0

We move all terms containing X to the left, all other terms to the right

-3X=-21

X=-21/-3

X=+7

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