X(x+1)=x-2(x+5)

Solution for X(x+1)=x-2(x+5) equation:

X(X+1)=X-2(X+5)

We move all terms to the left:

X(X+1)-(X-2(X+5))=0

We multiply parentheses

X^2+X-(X-2(X+5))=0


We calculate terms in parentheses: -(X-2(X+5)), so:

X-2(X+5)

We multiply parentheses

X-2X-10

We add all the numbers together, and all the variables

-1X-10

Back to the equation:

-(-1X-10)


We get rid of parentheses

X^2+X+1X+10=0

We add all the numbers together, and all the variables

X^2+2X+10=0

a = 1; b = 2; c = +10;
Δ = b2-4ac
Δ = 22-4·1·10
Δ = -36
Delta is less than zero, so there is no solution for the equation