X(x+10)+x(x+25)+5=195

Solution for X(x+10)+x(x+25)+5=195 equation:

X(X+10)+X(X+25)+5=195

We move all terms to the left:

X(X+10)+X(X+25)+5-(195)=0

We add all the numbers together, and all the variables

X(X+10)+X(X+25)-190=0

We multiply parentheses

X^2+X^2+10X+25X-190=0

We add all the numbers together, and all the variables

2X^2+35X-190=0

a = 2; b = 35; c = -190;
Δ = b2-4ac
Δ = 352-4·2·(-190)
Δ = 2745
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2745}=\sqrt{9*305}=\sqrt{9}*\sqrt{305}=3\sqrt{305}$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(35)-3\sqrt{305}}{2*2}=\frac{-35-3\sqrt{305}}{4}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(35)+3\sqrt{305}}{2*2}=\frac{-35+3\sqrt{305}}{4}
$