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X(X+10)=2000
We move all terms to the left:
X(X+10)-(2000)=0
We multiply parentheses
X^2+10X-2000=0
a = 1; b = 10; c = -2000;
Δ = b2-4ac
Δ = 102-4·1·(-2000)
Δ = 8100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{8100}=90$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-90}{2*1}=\frac{-100}{2} =-50 $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+90}{2*1}=\frac{80}{2} =40 $
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