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X(X+11)=312
We move all terms to the left:
X(X+11)-(312)=0
We multiply parentheses
X^2+11X-312=0
a = 1; b = 11; c = -312;
Δ = b2-4ac
Δ = 112-4·1·(-312)
Δ = 1369
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1369}=37$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-37}{2*1}=\frac{-48}{2} =-24 $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+37}{2*1}=\frac{26}{2} =13 $
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