X(x+12)=(x+2)(x+5)

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Solution for X(x+12)=(x+2)(x+5) equation: 



X(X+12)=(X+2)(X+5)

We move all terms to the left:

X(X+12)-((X+2)(X+5))=0

We multiply parentheses

X^2+12X-((X+2)(X+5))=0

We multiply parentheses ..

X^2-((+X^2+5X+2X+10))+12X=0



We calculate terms in parentheses: -((+X^2+5X+2X+10)), so:

(+X^2+5X+2X+10)

We get rid of parentheses

X^2+5X+2X+10

We add all the numbers together, and all the variables

X^2+7X+10

Back to the equation:

-(X^2+7X+10)



We add all the numbers together, and all the variables

X^2+12X-(X^2+7X+10)=0

We get rid of parentheses

X^2-X^2+12X-7X-10=0

We add all the numbers together, and all the variables

5X-10=0

We move all terms containing X to the left, all other terms to the right

5X=10

X=10/5

X=2

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