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X(X+15)=2250
We move all terms to the left:
X(X+15)-(2250)=0
We multiply parentheses
X^2+15X-2250=0
a = 1; b = 15; c = -2250;
Δ = b2-4ac
Δ = 152-4·1·(-2250)
Δ = 9225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{9225}=\sqrt{225*41}=\sqrt{225}*\sqrt{41}=15\sqrt{41}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-15\sqrt{41}}{2*1}=\frac{-15-15\sqrt{41}}{2} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+15\sqrt{41}}{2*1}=\frac{-15+15\sqrt{41}}{2} $
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