X(x+2)+1=(x+2)(x+4)

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Solution for X(x+2)+1=(x+2)(x+4) equation: 



X(X+2)+1=(X+2)(X+4)

We move all terms to the left:

X(X+2)+1-((X+2)(X+4))=0

We multiply parentheses

X^2+2X-((X+2)(X+4))+1=0

We multiply parentheses ..

X^2-((+X^2+4X+2X+8))+2X+1=0



We calculate terms in parentheses: -((+X^2+4X+2X+8)), so:

(+X^2+4X+2X+8)

We get rid of parentheses

X^2+4X+2X+8

We add all the numbers together, and all the variables

X^2+6X+8

Back to the equation:

-(X^2+6X+8)



We add all the numbers together, and all the variables

X^2+2X-(X^2+6X+8)+1=0

We get rid of parentheses

X^2-X^2+2X-6X-8+1=0

We add all the numbers together, and all the variables

-4X-7=0

We move all terms containing X to the left, all other terms to the right

-4X=7

X=7/-4

X=-1+3/4

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