X(x+2)3(x+2)=68

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Solution for X(x+2)3(x+2)=68 equation:


Simplifying
X(x + 2) * 3(x + 2) = 68

Reorder the terms:
X(2 + x) * 3(x + 2) = 68

Reorder the terms:
X(2 + x) * 3(2 + x) = 68

Reorder the terms for easier multiplication:
3X(2 + x)(2 + x) = 68

Multiply (2 + x) * (2 + x)
3X(2(2 + x) + x(2 + x)) = 68
3X((2 * 2 + x * 2) + x(2 + x)) = 68
3X((4 + 2x) + x(2 + x)) = 68
3X(4 + 2x + (2 * x + x * x)) = 68
3X(4 + 2x + (2x + x2)) = 68

Combine like terms: 2x + 2x = 4x
3X(4 + 4x + x2) = 68
(4 * 3X + 4x * 3X + x2 * 3X) = 68
(12X + 12xX + 3x2X) = 68

Solving
12X + 12xX + 3x2X = 68

Solving for variable 'X'.

Move all terms containing X to the left, all other terms to the right.

Reorder the terms:
-68 + 12X + 12xX + 3x2X = 68 + -68

Combine like terms: 68 + -68 = 0
-68 + 12X + 12xX + 3x2X = 0

The solution to this equation could not be determined.

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