X(x+2)=(x+12)(x-2)

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Solution for X(x+2)=(x+12)(x-2) equation: 



X(X+2)=(X+12)(X-2)

We move all terms to the left:

X(X+2)-((X+12)(X-2))=0

We multiply parentheses

X^2+2X-((X+12)(X-2))=0

We multiply parentheses ..

X^2-((+X^2-2X+12X-24))+2X=0



We calculate terms in parentheses: -((+X^2-2X+12X-24)), so:

(+X^2-2X+12X-24)

We get rid of parentheses

X^2-2X+12X-24

We add all the numbers together, and all the variables

X^2+10X-24

Back to the equation:

-(X^2+10X-24)



We add all the numbers together, and all the variables

X^2+2X-(X^2+10X-24)=0

We get rid of parentheses

X^2-X^2+2X-10X+24=0

We add all the numbers together, and all the variables

-8X+24=0

We move all terms containing X to the left, all other terms to the right

-8X=-24

X=-24/-8

X=+3

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