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X(X+2)=1000
We move all terms to the left:
X(X+2)-(1000)=0
We multiply parentheses
X^2+2X-1000=0
a = 1; b = 2; c = -1000;
Δ = b2-4ac
Δ = 22-4·1·(-1000)
Δ = 4004
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{4004}=\sqrt{4*1001}=\sqrt{4}*\sqrt{1001}=2\sqrt{1001}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2\sqrt{1001}}{2*1}=\frac{-2-2\sqrt{1001}}{2} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2\sqrt{1001}}{2*1}=\frac{-2+2\sqrt{1001}}{2} $
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