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X(X+2)=123
We move all terms to the left:
X(X+2)-(123)=0
We multiply parentheses
X^2+2X-123=0
a = 1; b = 2; c = -123;
Δ = b2-4ac
Δ = 22-4·1·(-123)
Δ = 496
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{496}=\sqrt{16*31}=\sqrt{16}*\sqrt{31}=4\sqrt{31}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-4\sqrt{31}}{2*1}=\frac{-2-4\sqrt{31}}{2} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+4\sqrt{31}}{2*1}=\frac{-2+4\sqrt{31}}{2} $
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