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X(X+20)=156
We move all terms to the left:
X(X+20)-(156)=0
We multiply parentheses
X^2+20X-156=0
a = 1; b = 20; c = -156;
Δ = b2-4ac
Δ = 202-4·1·(-156)
Δ = 1024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1024}=32$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(20)-32}{2*1}=\frac{-52}{2} =-26 $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(20)+32}{2*1}=\frac{12}{2} =6 $
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