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X(X+20)=2816
We move all terms to the left:
X(X+20)-(2816)=0
We multiply parentheses
X^2+20X-2816=0
a = 1; b = 20; c = -2816;
Δ = b2-4ac
Δ = 202-4·1·(-2816)
Δ = 11664
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{11664}=108$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(20)-108}{2*1}=\frac{-128}{2} =-64 $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(20)+108}{2*1}=\frac{88}{2} =44 $
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