X(x+3)-3=x(x-5)-19

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Solution for X(x+3)-3=x(x-5)-19 equation: 



X(X+3)-3=X(X-5)-19

We move all terms to the left:

X(X+3)-3-(X(X-5)-19)=0

We multiply parentheses

X^2+3X-(X(X-5)-19)-3=0



We calculate terms in parentheses: -(X(X-5)-19), so:

X(X-5)-19

We multiply parentheses

X^2-5X-19

Back to the equation:

-(X^2-5X-19)



We get rid of parentheses

X^2-X^2+3X+5X+19-3=0

We add all the numbers together, and all the variables

8X+16=0

We move all terms containing X to the left, all other terms to the right

8X=-16

X=-16/8

X=-2

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