X(x+3)=-2(x+3)

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Solution for X(x+3)=-2(x+3) equation:



X(X+3)=-2(X+3)
We move all terms to the left:
X(X+3)-(-2(X+3))=0
We multiply parentheses
X^2+3X-(-2(X+3))=0
We calculate terms in parentheses: -(-2(X+3)), so:
-2(X+3)
We multiply parentheses
-2X-6
Back to the equation:
-(-2X-6)
We get rid of parentheses
X^2+3X+2X+6=0
We add all the numbers together, and all the variables
X^2+5X+6=0
a = 1; b = 5; c = +6;
Δ = b2-4ac
Δ = 52-4·1·6
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-1}{2*1}=\frac{-6}{2} =-3 $
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+1}{2*1}=\frac{-4}{2} =-2 $

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