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X(X+4)=480
We move all terms to the left:
X(X+4)-(480)=0
We multiply parentheses
X^2+4X-480=0
a = 1; b = 4; c = -480;
Δ = b2-4ac
Δ = 42-4·1·(-480)
Δ = 1936
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1936}=44$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-44}{2*1}=\frac{-48}{2} =-24 $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+44}{2*1}=\frac{40}{2} =20 $
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