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X(X+5)=X(X+3)+6
We move all terms to the left:
X(X+5)-(X(X+3)+6)=0
We multiply parentheses
X^2+5X-(X(X+3)+6)=0
We calculate terms in parentheses: -(X(X+3)+6), so:We get rid of parentheses
X(X+3)+6
We multiply parentheses
X^2+3X+6
Back to the equation:
-(X^2+3X+6)
X^2-X^2+5X-3X-6=0
We add all the numbers together, and all the variables
2X-6=0
We move all terms containing X to the left, all other terms to the right
2X=6
X=6/2
X=3
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