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X(X-17)18=(X-3)(X+16)
We move all terms to the left:
X(X-17)18-((X-3)(X+16))=0
We multiply parentheses
18X^2-306X-((X-3)(X+16))=0
We multiply parentheses ..
18X^2-((+X^2+16X-3X-48))-306X=0
We calculate terms in parentheses: -((+X^2+16X-3X-48)), so:We add all the numbers together, and all the variables
(+X^2+16X-3X-48)
We get rid of parentheses
X^2+16X-3X-48
We add all the numbers together, and all the variables
X^2+13X-48
Back to the equation:
-(X^2+13X-48)
18X^2-306X-(X^2+13X-48)=0
We get rid of parentheses
18X^2-X^2-306X-13X+48=0
We add all the numbers together, and all the variables
17X^2-319X+48=0
a = 17; b = -319; c = +48;
Δ = b2-4ac
Δ = -3192-4·17·48
Δ = 98497
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-319)-\sqrt{98497}}{2*17}=\frac{319-\sqrt{98497}}{34} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-319)+\sqrt{98497}}{2*17}=\frac{319+\sqrt{98497}}{34} $
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