X(x-3)(x-4)+3(x-2)(x-4)=19(x-4)(x-3)

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Solution for X(x-3)(x-4)+3(x-2)(x-4)=19(x-4)(x-3) equation: 



X(X-3)(X-4)+3(X-2)(X-4)=19(X-4)(X-3)

We move all terms to the left:

X(X-3)(X-4)+3(X-2)(X-4)-(19(X-4)(X-3))=0

We multiply parentheses ..

X(+X^2-4X-3X+12)+3(X-2)(X-4)-(19(X-4)(X-3))=0



We calculate terms in parentheses: -(19(X-4)(X-3)), so:

19(X-4)(X-3)

We multiply parentheses ..

19(+X^2-3X-4X+12)

We multiply parentheses

19X^2-57X-76X+228

We add all the numbers together, and all the variables

19X^2-133X+228

Back to the equation:

-(19X^2-133X+228)



We multiply parentheses

X^3-4X^2-3X^2+12X+3(X-2)(X-4)-(19X^2-133X+228)=0

We get rid of parentheses

X^3-4X^2-3X^2-19X^2+12X+3(X-2)(X-4)+133X-228=0

We multiply parentheses ..

X^3-4X^2-3X^2-19X^2+3(+X^2-4X-2X+8)+12X+133X-228=0

We do not support eXpression: X^3

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