X(x-4)-2=x2-4(x+3)

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Solution for X(x-4)-2=x2-4(x+3) equation: 



X(X-4)-2=X2-4(X+3)

We move all terms to the left:

X(X-4)-2-(X2-4(X+3))=0

We multiply parentheses

X^2-4X-(X2-4(X+3))-2=0



We calculate terms in parentheses: -(X2-4(X+3)), so:

X2-4(X+3)

We add all the numbers together, and all the variables

X^2-4(X+3)

We multiply parentheses

X^2-4X-12

Back to the equation:

-(X^2-4X-12)



We get rid of parentheses

X^2-X^2-4X+4X+12-2=0

We add all the numbers together, and all the variables

10!=0

There is no solution for this equation

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