X(x-5)+10=(x+2)(x+4)

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Solution for X(x-5)+10=(x+2)(x+4) equation:



X(X-5)+10=(X+2)(X+4)
We move all terms to the left:
X(X-5)+10-((X+2)(X+4))=0
We multiply parentheses
X^2-5X-((X+2)(X+4))+10=0
We multiply parentheses ..
X^2-((+X^2+4X+2X+8))-5X+10=0
We calculate terms in parentheses: -((+X^2+4X+2X+8)), so:
(+X^2+4X+2X+8)
We get rid of parentheses
X^2+4X+2X+8
We add all the numbers together, and all the variables
X^2+6X+8
Back to the equation:
-(X^2+6X+8)
We add all the numbers together, and all the variables
X^2-5X-(X^2+6X+8)+10=0
We get rid of parentheses
X^2-X^2-5X-6X-8+10=0
We add all the numbers together, and all the variables
-11X+2=0
We move all terms containing X to the left, all other terms to the right
-11X=-2
X=-2/-11
X=2/11

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