X(x-5)+10=(x+2)(x+4)

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Solution for X(x-5)+10=(x+2)(x+4) equation: 



X(X-5)+10=(X+2)(X+4)

We move all terms to the left:

X(X-5)+10-((X+2)(X+4))=0

We multiply parentheses

X^2-5X-((X+2)(X+4))+10=0

We multiply parentheses ..

X^2-((+X^2+4X+2X+8))-5X+10=0



We calculate terms in parentheses: -((+X^2+4X+2X+8)), so:

(+X^2+4X+2X+8)

We get rid of parentheses

X^2+4X+2X+8

We add all the numbers together, and all the variables

X^2+6X+8

Back to the equation:

-(X^2+6X+8)



We add all the numbers together, and all the variables

X^2-5X-(X^2+6X+8)+10=0

We get rid of parentheses

X^2-X^2-5X-6X-8+10=0

We add all the numbers together, and all the variables

-11X+2=0

We move all terms containing X to the left, all other terms to the right

-11X=-2

X=-2/-11

X=2/11

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