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X(X-4)+4X=2598
We move all terms to the left:
X(X-4)+4X-(2598)=0
We add all the numbers together, and all the variables
4X+X(X-4)-2598=0
We multiply parentheses
X^2+4X-4X-2598=0
We add all the numbers together, and all the variables
X^2-2598=0
a = 1; b = 0; c = -2598;
Δ = b2-4ac
Δ = 02-4·1·(-2598)
Δ = 10392
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{10392}=\sqrt{4*2598}=\sqrt{4}*\sqrt{2598}=2\sqrt{2598}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{2598}}{2*1}=\frac{0-2\sqrt{2598}}{2} =-\frac{2\sqrt{2598}}{2} =-\sqrt{2598} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{2598}}{2*1}=\frac{0+2\sqrt{2598}}{2} =\frac{2\sqrt{2598}}{2} =\sqrt{2598} $
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