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X(X+12)=493
We move all terms to the left:
X(X+12)-(493)=0
We multiply parentheses
X^2+12X-493=0
a = 1; b = 12; c = -493;
Δ = b2-4ac
Δ = 122-4·1·(-493)
Δ = 2116
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2116}=46$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-46}{2*1}=\frac{-58}{2} =-29 $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+46}{2*1}=\frac{34}{2} =17 $
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