X*4x=140

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Solution for X*4x=140 equation:



X*4X=140
We move all terms to the left:
X*4X-(140)=0
Wy multiply elements
4X^2-140=0
a = 4; b = 0; c = -140;
Δ = b2-4ac
Δ = 02-4·4·(-140)
Δ = 2240
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{2240}=\sqrt{64*35}=\sqrt{64}*\sqrt{35}=8\sqrt{35}$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-8\sqrt{35}}{2*4}=\frac{0-8\sqrt{35}}{8} =-\frac{8\sqrt{35}}{8} =-\sqrt{35} $
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+8\sqrt{35}}{2*4}=\frac{0+8\sqrt{35}}{8} =\frac{8\sqrt{35}}{8} =\sqrt{35} $

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