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X*4X=380
We move all terms to the left:
X*4X-(380)=0
Wy multiply elements
4X^2-380=0
a = 4; b = 0; c = -380;
Δ = b2-4ac
Δ = 02-4·4·(-380)
Δ = 6080
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{6080}=\sqrt{64*95}=\sqrt{64}*\sqrt{95}=8\sqrt{95}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-8\sqrt{95}}{2*4}=\frac{0-8\sqrt{95}}{8} =-\frac{8\sqrt{95}}{8} =-\sqrt{95} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+8\sqrt{95}}{2*4}=\frac{0+8\sqrt{95}}{8} =\frac{8\sqrt{95}}{8} =\sqrt{95} $
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